Question

Factorise : x⁶-64 fast​

Answer 1

$\huge\tt\red{Answer}$

$x^6-64$

$(x^2)^3-(4^2)$

$(x^2-4)(x^4-4x^2+16)$

$(x+2)(x-2)(x^4+4x^2+16)$

Answer 2

Answer:

Step-by-step explanation:

x⁶ - 2⁶

(x³)² - (2³)²

-----a² - b² = (a+b)(a-b)

(x³+2³)(x³-2³)

----a³ + b³ = (a + b)(a² - ab + b²)

----a³ – b³ = (a – b)(a² + ab + b²)

(x+2)(x²-2x+4)(x-2)(x²+2x+4)