factorise y^2+7y-18.......?
Answers
Answered by
17
y^2 +7y-18 = 0
y^2 + 9y-2y-18=0
y(y+9)-2(y+9) = 0
(y+9)(y-2) = 0
Now,hence,
y^2 + 7y - 18 = (y+9)(y-2)
y^2 + 9y-2y-18=0
y(y+9)-2(y+9) = 0
(y+9)(y-2) = 0
Now,hence,
y^2 + 7y - 18 = (y+9)(y-2)
Similar questions