Question

rupees 6000 for 2 year at 9 per annum compounded annually

Answer 1

Answer:

Amount = $P ( 1 + R / 100 )^T$

Given :

• Principal = Rs. 6000
• Time Period = 2 years
• Rate of interest = 9%

Substituting in the formula we get,

=> Amount = 6000 ( 1 + 9 / 100 )²

=> Amount = 6000 ( 1 + 0.09 )²

=> Amount = 6000 ( 1.09 )²

=> Amount = 6000 ( 1.1881 )

=> Amount = 7128.60

Hence the amount is Rs. 7128.60

Compound Interest = Amount - Principal

=> CI = 7128.6 - 6000.0

=> CI = 1128.6

Hence it is the required answer.

Answer 2

✨HELLO MATE ✨

ANSWER
⬇️ ⬇️ ⬇️ ⬇️ ⬇️ ⬇️

➡️ Amount = P ( 1+ r/100) ^ T

➡️ Given : Principal ↪️₹ 6000
Time↪️2 year
Interest ↪️9 %

PUT THESE VALUES IN THE FORMULA

↪️A = 6000(1 + 9/100) ^2
↪️A = 6000(1+9/100)^2
↪️A=6000( 1= 0.009)^2
↪️A=6000 ×( 1.09)^2
↪️A= 6000×1. 1881
➡️ Amount = 7128.60


↗️↗️↗️↗️Hence amount is ₹7128.60

HOPE IT WILL HELP YOU

BE BRAINLY ♣️ ⚗️ ☸️ ⭐