factorise- y3-3y2-y+3
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it may help u..
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navyarajiv:
its not clear
but anyway thanks
lemme show you what she did.
y^3-3y^2-y+3=y^2(y-3) - 1(y-3)= (y^2-1)(y-3)
= {(Y) ^2 - (1)^2}(y-3)= (y-1)(y+1)(y-3)
your answer is (y-1)(y+1)(y-3)
thankssss
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