factorise (z²-z-3)(z²-z+1)+4
Answers
Answered by
1
Answer:
z^{4}-2z^{3}-z^{2}+2z+1
Step-by-step explanation:
( z ^ { 2 } - z - 3 ) ( z ^ { 2 } - z + 1 ) + 4
z^{4}-2z^{3}-z^{2}+2z-3+4
z^{4}-2z^{3}-z^{2}+2z+1
Answered by
1
Answer:
z^4+z+1
Step-by-step explanation:
(z^2-z-3)(z^2-z+1)+4
= (z^4+z-3)+4
= z^4+z+1
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