Question

factorised. 2t2-t-10

Answer 1

$2t {}^{2} - t - 10 \\ 2t2 - 5t + 4t - 10 \\ t(2t - 5) + 2(2t - 5) \\ (t + 2)(2t - 5)$
I hope it helps you

Answer 2

Given,

The quadratic equation 2t²-t-10 is given.

To find,

We have to find the factors of the given quadratic equation 2t²-t-10.

Solution,

The factors of 2t²-t-10 are(2t-5)(t+2).

We can simply factorize the quadratic equation 2t²-t-10  by using the quadratic formula,

  D = b²-4ac

  D = (-1)² - 4(2)(-10)

  D = 1+80

  D = 81

   t = -b±√D/2a

   t = 1± √81/4

   t = 1± 9/4

   t = 10/4 , -8/4

   t = 5/2 , -2

   (2t-5)(t+2)

Hence, the factors of 2t²-t-10 are (2t-5)(t+2).