Question

factorised y^3-7y+6​

Answer 1

$\huge \bold{Factorisation :}$

⭐ y³ - 7y + 6 ⭐

Multiple 6 with y³ = 6y³

Then find the factors of 6y³

= 6×1

= 2×3

When you do the operation of 6 + 1 you get 7. Which will be the middle term of the question.

Hence, the equation would be =

y³ + 6y + y + 6

Take things common.

y ( y+ 6 ) 1 ( y + 6 )

= ( y + 6 ) ( y + 1 )

Answer 2

Answer:

(y +6) (y ² + 1)

step by step explanation

According to the rules we should multiply y³ with 6

So,

y³ × 6 = 6y³

Now,

According to the rules of factorisation on this equation ,we should get 7y on adding such a number whose product is 6y³

ATQ,

y³ + 6y² + y + 6

Now,

Divide it into two terms

(y³+6y²) + (y+6)

Taking y as common for first term and 1 for second term we get -

y²(y+6) + 1(y+6)

=> (y² + 1) (y + 6)

Hope it helps you

Thanks