factorisse 2y^3+y^2-2y-1
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Answered by
8
2y³+y²-2y-1
=> 2y²(y-1)+3y(y-1)+1(y-1)
=> (y-1)(2y²+3y+1)
=> (y-1)(2y²+2y+1y+1)
=> (y-1)[2y(y+1)+1(y+1)]
=> (y-1)(y+1)(2y+1)
Hope this helps!
Answered by
7
hey.!!!
factorisse 2y^3+y^2-2y-1
Solution :-
2y^3+y^2-2y-1
=2y³-2y²+3y²-3y+y-1
=2y²(y-1)+3y(y-1)+1(y-1)
=(y-1)(2y²+3y+1)
=(2y²+2y+y+1)(y-1)
=[2y(y+1)+1(y+1)](y-1)
=(2y+1)(y+1)(y-1)
i hopes its help's u
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