Question

factorizacion de 4x^4 - 4x^2y + y^2

Answer 1

Answer:

4x^4-4x^2y+y^2=0

4x^4-2x^2y-2x^2y+y^2=0

2x^2(2x^2-y)-y(2x^2-y)=0

(2x^2-y)(2x^2-y)=0

2x^2-y=0, 2x^2-y=0

2x^2=y, 2x^2=y

x^2=y/2, x^2=y/2

x=√y/√2, x=√y/√2.

Here is your answer.