Question

factorization: (3a+5b)²-4c²​

Answer 1

(3a+5b)^2-4c^2

So, here the given expression is in the form of a^2-b^2= (a+b)(a-b)

ON APPLYING THE ABOVE FORMULA WE GET,

(3a+5b)^2-4c^2

=(3a+5b+4c)(3a+5b-4c) as the answer .

HOPE THIS WILL HELP YOU

Answer 2

★ Answer :

→ Method 1 :

As, we have to factorise the (3a + 5b)² - 4c²

We know that,

(a + b)² = a² + b² + 2ab

→ (3a)² + (5b)² + 2(3a)(5b) - 4c²

→ 9a² + 25b² - 4c² + 30ab

$\rule{200}{2}$

→ Method 2 :

→ (3a + 5b)² - 4c²

We can write 4c² as (2c)².

→ (3a + 5b)² - (2c)²

We know that,

a² - b² = (a + b)(a - b)

→ (3a + 5b - 2c)(3a + 5b + 2c)

→ 9a² + 15ab - 6ac + 15ab + 25b² - 10bc + 6ac + 10bc - 4c²

→ 9a² + 25b² - 4c² + 30ab