factorization of (x+y)²+9(x+y)+8 is
Answers
Answered by
3
Answer:
By middle term factorisation:
(x+y)² +9(x+y)+8
let (x+y) be a.
a² + 9a + 8
a² + 8a + a + 8
a(a+8)+1(a+8)
(a+8)(a+1)
(x+y+8)(x+y+1)
Hopes it helps!
Answered by
5
Step-by-step explanation:
2(x + y)² - 9( x + y ) -5 = 0
⇒2(x + y)² - 10 (x+y) +1(x+y) -5 = 0
⇒2(x+y)(x + y - 5 ) + 1(x + y -5 ) = 0
taking (x + y -5 ) common ,
⇒(x + y -5 )[2(x + y) + 1] =0
⇒(x + y -5)(2x + 2y +1) =0
Similar questions