Question

factorize 27x^3+y^3+2^3-9xyz

Answer 1

Final Answer :
(3x+y+z)(9x^2+y^2+z^2-3xy-yz--3xz)


We know that,
$( {a}^{3} + {b}^{3} + {c}^{3} - 3abc) = \\ (a + b + c)( {a}^{2} + {b}^{2} + {c}^{2} \\ - ab - bc - ca)$


Here,
Put a = 3x, b = y, c = z
To get
(3x+y+z)(9x^2+y^2+z^2-3xy-yz-3zx)