Question

factorize 2x^3 + 3x^2 - 11x - 6 using factor thereom​

Answer 1

Answer:

Now, 2x+1=0

⇒x=-1/2

f(x)=2x³+3x²-11x-6

⇒f(-1/2)=2(-1/2)³+3(-1/2)²-11(-1/2)-6

            =2(-1/8)+3(1/4)+(11/2)-6

            =(-1/4)+(3/4)+(11/2)-6

            =(-1+3+22-24)÷4

            =0/4

            =0

∴(2x+1) is a factor of 2x³+3x²-11x-6