Math, asked by nehasaini83, 10 months ago

factorize 3√3a^3 -b^3 -5√5c^3 -3 √15 abc​

Answers

Answered by shreyash234
36

Answer:

(√3a-b-√5c) (3a^2+b^2+5c^2+√3ab-√5bc+√15ac)

Step-by-step explanation:

(√3a)^3+(-b)^3+(-√5c)^3-3(√3a)(-b)(-√5c)

By using following formula

a^3+b^3+c^3-3abc=(a+b+c) (a^2+b^2+c^2-ab-bc-ca)

=(√3a-b-√5c) (3a^2+b^2+5c^2+√3ab-√5bc+√15ac)

Answered by vedant6788
2

Answer:

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