Physics, asked by lokesh386, 1 year ago

One mole of an ideal gas expands at a constant tempera
of 300 K from an initial volume of 10 litres to a final volu
of 20 litres. The work done in expanding the gas is
(R = 8.31 J/mole-K)
[MP PMT 1995; UPSEAT 2000; J & K CET 20
(a) 750 joules
(b) 1728 joules
(c) 1500 joules
(d) 3456 joules
nf a gas at 0.8 m pressure​

Answers

Answered by mehtapayal2000
3

Answer:

(b) 1728

Explanation:

Given :

n=1 , T=300k , V₁=10L , V₂=20L ,R=8.31J/mol-k

W = 2.303 RT log₁₀ (V2/V1)

   =2.303 ×8.31×300×㏒₁₀(20/10)

   =1728 J

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