Question

factorize 3x^3+4x^2-12x+16

Answer 1

Factorize 3x^3 - 4x^2 - 12x + 16

Step  1  :Equation at the end of step  1  : (((3 • (x3)) - 22x2) - 12x) - 16 = 0
Step  2  :Equation at the end of step  2  : ((3x3 - 22x2) - 12x) - 16 = 0 Step  3  :Checking for a perfect cube :
 3.1    3x3-4x2-12x-16  is not a perfect cube 

Trying to factor by pulling out :
 3.2      Factoring:  3x3-4x2-12x-16 

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1:  3x3-16 
Group 2:  -4x2-12x 

Pull out from each group separately :

Group 1:   (3x3-16) • (1)
Group 2:   (x+3) • (-4x)

Step  2  :Equation at the end of step  2  : ((3x3 - 22x2) - 12x) - 16 = 0
Step  3  :Checking for a perfect cube :

 3.1    3x3-4x2-12x-16  is not a perfect cube 

Trying to factor by pulling out :
 3.2      Factoring:  3x3-4x2-12x-16 

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1:  3x3-16 
Group 2:  -4x2-12x 

Pull out from each group separately :

Group 1:   (3x3-16) • (1)
Group 2:   (x+3) • (-4x)

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