Factorize 50a²-2(b-c)²
Answers
= 2 [ 25a²-(b-c)²]
= 2 [ (5a)²-(b-c)²]
using the identity, a²-b²=(a+b)(a-b)
where a = 5a, b= (b-c)
= 2 (5a+b-c) ( 5a-b+c)...
Answer:
Answer:answer is 2(5a+b-c)(5a-b+c)
Answer:answer is 2(5a+b-c)(5a-b+c)Step-by-step explanation:
Answer:answer is 2(5a+b-c)(5a-b+c)Step-by-step explanation:firsr we have to take common from both
Answer:answer is 2(5a+b-c)(5a-b+c)Step-by-step explanation:firsr we have to take common from bothso from 50a²-2(b-c) we will take 2as a common
Answer:answer is 2(5a+b-c)(5a-b+c)Step-by-step explanation:firsr we have to take common from bothso from 50a²-2(b-c) we will take 2as a common so the answer will be
Answer:answer is 2(5a+b-c)(5a-b+c)Step-by-step explanation:firsr we have to take common from bothso from 50a²-2(b-c) we will take 2as a common so the answer will be2(25a²-(b-c)²)
Answer:answer is 2(5a+b-c)(5a-b+c)Step-by-step explanation:firsr we have to take common from bothso from 50a²-2(b-c) we will take 2as a common so the answer will be2(25a²-(b-c)²)2((5a)²-(b-c)²)
Answer:answer is 2(5a+b-c)(5a-b+c)Step-by-step explanation:firsr we have to take common from bothso from 50a²-2(b-c) we will take 2as a common so the answer will be2(25a²-(b-c)²)2((5a)²-(b-c)²)this is in (a²-b²)=(a+b)(a-b)
Answer:answer is 2(5a+b-c)(5a-b+c)Step-by-step explanation:firsr we have to take common from bothso from 50a²-2(b-c) we will take 2as a common so the answer will be2(25a²-(b-c)²)2((5a)²-(b-c)²)this is in (a²-b²)=(a+b)(a-b)2(5a+b-c)(5a-b+c)