Factorize : a^2b^2 - 6abc + 9c^2
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Answer:
a2b2−6abc+9c2
a2b2−6abc+9c2=(ab)2+2×ab×(−3c)+(−3c)2
a2b2−6abc+9c2=(ab)2+2×ab×(−3c)+(−3c)2Using a2+b2−2ab=(a−b)2
a2b2−6abc+9c2=(ab)2+2×ab×(−3c)+(−3c)2Using a2+b2−2ab=(a−b)2=(ab−3c)2
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