Question

factorize:
a) 8a³+b³+12a²b+6ab²
b) 27y³+125z³
c) 27x³+y³+z³-9xyz​

Answer 1

Answer:

a.Hey there!

\begin{gathered} {8a}^{3} - {b}^{3} - 12 {a}^{2} b + 6a {b}^{2} \\ \\ = ( {2a})^{3} + ( { - b})^{3} + 3(2a) ( - b) (2 a - b) \\ \\ = (2a - b) ^{3} \\ \\ = (2a - b)(2a - b)(2a - b) \\ \\ \end{gathered}

8a

3

−b

3

−12a

2

b+6ab

2

=(2a)

3

+(−b)

3

+3(2a)(−b)(2a−b)

=(2a−b)

3

=(2a−b)(2a−b)(2a−b)

\begin{gathered} \textsf{formulae} \\ \\ {(a - b)}^{3} = { a}^{3} - {b}^{3} - 3ab(a - b) \\ \\ \end{gathered}

formulae

(a−b)

3

=a

3

−b

3

−3ab(a−b)

Hope helped!

Answer 2

Answer:

a. (2a+b)*(2a+b)*(2a+b)

b. (3y+5z)(9y²-15yz+25z²)

c. (3x+y+z)(9x²+y²+z²-3xy-yz-3xz)

Step-by-step explanation:

Hope it helps you.