Factorize
this is the factorization problem....
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....Heya your answer is here....
....But I am not sure with my answer...
....But I am not sure with my answer...
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☺️ Hey mate! here's your answer!☺️
QUESTION = a² - b² - 2b - 1
solution =
we will use the identity,
( a + b)² = a² + 2ab + b²
so,
a² - b² - 2b - 1
= a² - [ (b)² + 2(1)(b) + (1)² ]
= a² - ( b + 1 )²
then, again another identity will be used,
a² - b² = (a+b)(a-b)
therefore,
= a² - ( b + 1 )²
= (a + b + 1)(a - b - 1) ....Answer!
hope it is helpful ✌️!
QUESTION = a² - b² - 2b - 1
solution =
we will use the identity,
( a + b)² = a² + 2ab + b²
so,
a² - b² - 2b - 1
= a² - [ (b)² + 2(1)(b) + (1)² ]
= a² - ( b + 1 )²
then, again another identity will be used,
a² - b² = (a+b)(a-b)
therefore,
= a² - ( b + 1 )²
= (a + b + 1)(a - b - 1) ....Answer!
hope it is helpful ✌️!
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