Question

factorize using factor theorem y³-2y²-29y-42​

Answer 1

By factorization of , the factors are (y+3)(y-7)(y+2)

Solution:

By trial, f(1) ≠ 0,f(-1) ≠ 0,f(2) ≠ 0,f(-2) = 0

Hence y+2 is a factor.

f(-2) = (-8) – 2(4) + 58 – 42  

f(-2) = -16 + 58 – 42  

f(-2) = 0

The long division process is shown in the below attached image.

are the factors.

= y(y – 7) + 3(y – 7)( y+2)  

(y+3)(y-7)(y+2) are the factors.