factorize using identities
4a^2-12a^2+9
siddhartharao77:
I got -(8a^2 - 9) (or) -(2 root 2a+3)(2 root 2a-3) as answer.
Answers
Answered by
0
4a^2-6a-6a+9
2a(2a-3)-3(2a-3)
(2a-3)^2 =(2a-3)(2a-3)
2a(2a-3)-3(2a-3)
(2a-3)^2 =(2a-3)(2a-3)
Answered by
3
Hi ,
*************************************
We know the algebraic identity
( x - y )² = x² - 2xy + y²
***************************************
4a² - 12a + 9
= ( 2a )² - 2 × 2a × 3 + 3²
= ( 2a - 3 )²
= ( 2a - 3 ) ( 2a - 3 )
I hope this helps you.
:)
*************************************
We know the algebraic identity
( x - y )² = x² - 2xy + y²
***************************************
4a² - 12a + 9
= ( 2a )² - 2 × 2a × 3 + 3²
= ( 2a - 3 )²
= ( 2a - 3 ) ( 2a - 3 )
I hope this helps you.
:)
Similar questions