factorize
(x²+3x)² - 5(x²+3x) - y(x²+3y) + 5y
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Answer:
(x²+3x-5)(x²+3x-y)
Explanation:
(x²+3x)² - 5(x²+3x) - y(x²+3y) + 5y
= (x²+3x){(x²+3x) - 5} - y{(x²+3x) - 5}
= {(x²+3x) - 5}{(x²+3x) - y}
= (x²+3x-5)(x²+3x-y)
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