Factors of 8x3 + 27y3 are .
Answers
Answer:
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Step-by-step explanation:
Factors are (2x and 3 y) okay
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SOLUTION:-
Write (8x³- 27y³) in the form of (a³ - b³).
8x³ - 27y³ = (2x)³ - (3y)³
(2x)³ - (3y)³ is in the form of (a³ - b³).
Comparing (a³ - b³) and (2x)³ - (3y)³, we get
a = 2x
b = 3y
Write the formula for (a³ - b³) given in case 2 above.
a³ - b³ = (a - b)(a²+ ab + b²)
Substitute 2x for a and 3y for b.
(2x)³ - (3y)³ = (2x - 3y)[(2x)² + (2x)(3y) + (3y)²]
8x³ - 27y³ = (2x - 3y)(4x² + 6xy + 9y²)
General step for Factorising
•a³ - b³ = (a - b)³ + 3ab(a - b)
•a³ - b³ = (a - b)[(a - b)² + 3ab]
•a³ - b³ = (a - b)[a² - 2ab + b² + 3ab]
•a³ - b³ = (a - b)(a² + ab + b²)