Question

Father's age is three time the sum of his two sons after five years the are of father is two times the sum of the ages of his sons find the are of father

Answer 1

Answer:

45 Years

Step-by-step explanation:

Let say age of sons = S1    & S2    Years

Father Age = F   Years

Father's age is three time the sum of his two sons

F = 3 × ( S1 + S2)  

S1 + S2 = F/3    Eq 1

After 5 year

Father age will be  F+5  Years

Son1   would be  S1 + 5

Son2 Would be S2 + 5

After five years the age of father is two times the sum of the ages of his sons

F+5 = 2 (S1 + 5 + S2 + 5)

F + 5 = 2 ( S1 + S2) + 20

Putting S1 + S2 value from Eq 1

F + 5 = 2 (F/3)  + 20

F - 2F/3 = 15

3F - 2F = 45

F = 45

Father Age = 45 Years