Feather is dropped on the planet other than earth which has very low acceleration due to gravity from a height of 1.40 meters. The acceleration of gravity on the other planet is 1.67 m/s2. Determine the time of feather to fall to the surface of the other planet
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Feather is dropped on the planet other than earth which has very low acceleration due to gravity from a height of 1.40 meters. The acceleration of gravity on the other planet
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Explanation:
We have,
Final velocity (v) = ?
Initial velocity (u) = 0
Distance covered (s) =1.40
Acceleration (a) = 1.67 m/s2
V2=u2+2.a.s
Or, v2 = 0+2 x 1.67 x1.4
=4.676
Or, v = 2.16 m/sec
now,
v=u+at
or, t = (v-u)/a
=(2.16-0)/1.67
=1.294 sec
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