Fig 11.26
8. AABC is isosceles with AB = AC=7.5 cm and BC=9cm (Fig 11.26). The height
AD from A to BC. is 6 cm. Find the area of AABC. What will be the height from C
to AB ie.. CE?
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Answer:
Area = 27 square cm
CE = 7.2 cm
Step-by-step explanation:
Area of triangle is 1/2 * base * altitude
when taken BC as base
Area = 1/2* AD * BC
= 1/2 * 6 * 9= 27 square cm
when taken AB as base
Area = 1/2 * CE * AB
We know area is 27
27 = 1/2 * CE * 7.5
CE = 54/7.5
CE = 540/75= 7.2 cm
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