.Fill in the blank columns
V I P
200 V 2 A -------
250 -------- 750 W
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1
Explanation:
=
P
v
2
=
25
200
2
=1600Ω
R
2
=
100
200
2
=400Ω
When both bulbs are connected in series
V
1
=440×
R
1
+R
2
R
1
=440×
1600+400
1600
=352V;V
2
=440×
2500
400
=88V
Voltage across 25W bulb is greater than specified voltage, hence it will fuse
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