Question

fill in the blanks....​

Answer 1

ANSWER:-

i)

$\: \: \: \: \: {y}^{2} + 6y + 8 \\ \: \: \: \: \: \: \: \: \: \: = {y }^{2} + 4y + 2y + 8 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = y(y + 4) + 2(y + 4) \\ \: \: \: \: \: \: = (y + 2)(y + 4)$

SO, THE FIRST FIRST ANSWER IS (y+2) (y+4)

ii)

$3( {x}^{2} + 3x + 2) \\ \: \: \: \: \: \: \: \: \: \: = 3( {x}^{2} + 2x + 1x + 2) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 3(x(x + 2) + 1(x + 2)) \\ \: \: \: \: \: = 3((x + 2)(x + 1))$

SO THE SECOND ANSWER IS 3[ (x+2) (x+1) ]

iii)

$3( {x}^{2} + 8x + 12) \\ \: \: \: \: \: \: \: \: = 3({x}^{2} + 6x + 2x + 12) \\ \: \: \: \: \: \: \: \: \: \ \: = 3( x(x + 6) + 2(x + 6)) \\ =3 ((x + 2)(x + 6))$

SO THE THIRD ANSWER IS 3[ (x +2) (x+6) ]

iv)

$4 {p}^{2} + 12p + 5 \\ \: \: \: \: \: \: = 4 {p}^{2} + 10p + 2p + 5 \\ \: \: \: \: \: \: \: \: \: \: \: \: \ = 2p(2p + 5) + 1(2p + 5) \\ = (2p + 1)(2p + 5)$

SO THE FOURTH ANSWER IS (2p+1) (2p+5)

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