Question

Find 11th termfrom last term in ap 10,7,4....-62

Answer 1

Answer:

value of 11th term from last term of AP is  '-32'

Step-by-step explanation:

series in given AP

10, 7, 4, ... , -62

the difference in above series is '-3'

d = ( 7 - 10) = -3

first term is a₁ = 10

a₂ = 7 , a₃ = 4

let the last term be denoted as 'aₙ'

aₙ = - 62

formula to find last term of an AP is

aₙ = a₁ + (n - 1)d

- 62 = 10 + (n - 1)(-3)

- 62 - 10 = (-)(3)(n - 1)

- 72 = - (3)(n - 1)

(n - 1) = 72/3 = 24

n = 24 + 1 = 25

number of terms in given AP are '25'

also we have to find eleventh term from last term of AP

it is a₁₅

we have to find the value of a₁₅

a₁₅ = a₁ + (15 - 1)(d)

= 10 + 14(-3)

= 10 - (3)(14)

= 10 - 42

a₁₅ = - 32

value of 11th term from last term of AP is  '-32'