Math, asked by laasya7470, 6 days ago

find 2/5×-1/7+23/140-1/7×3/4
faster plss









Answers

Answered by namdeoshikhu777
3

Answer:

(i)

10

27

×4=

10

108

=10.8

(ii) =

100

271

×5=

100

1355

=13.55

(iii)

10

25

×

10

3

=

100

75

=0.75

(iv) =

10

23

×

100

435

=

1000

10005

=10.005

(v)

100

23806

×

10

75

=1785.45

(vi)

100

79

×

10

324

=25.596

(vii) =

100

107

×

100

2

=

10000

214

=0.0214

(viii)

100

1005

×

100

105

=10.5525

Answered by veekshyavellanki
10

Answer:

0

Step-by-step explanation:

2/5*-1/7+23/140-1/7*3/4= 2/5*-1/7-1/7*3/4+23/140 (by the commutative law of addition )

=2/5×(-1/7)+(-1/7)×3/4+23/140

=-1/7(2/5+3/4)+23/140

=-1/7(8+15/20)+23/140. ( by the distributive law )

= -1/7(23/20)+23/140

= -23/140+ -23/140. ( by the additive inverse law )

= 0

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