Question

find 3 consecutive integer whose product is equal to 16 times their sum

Answer 1

Hi friend,

Here is your answer,
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Let the numbers be (x-1) , x , (x+1).

(x-1)x(x+1) = 16{x-1+x+x+1}
=>   x³ - x   = 48x
=>      x³     = 49x
=>       x²    = 49
=>       x     = 7

The numbers are 6 , 7 and 8.
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