find 3 consecutive integer whose product is equal to 16 times their sum
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Hi friend,
Here is your answer,
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Let the numbers be (x-1) , x , (x+1).
(x-1)x(x+1) = 16{x-1+x+x+1}
=> x³ - x = 48x
=> x³ = 49x
=> x² = 49
=> x = 7
The numbers are 6 , 7 and 8.
______________________________________________________________
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Here is your answer,
______________________________________________________________
Let the numbers be (x-1) , x , (x+1).
(x-1)x(x+1) = 16{x-1+x+x+1}
=> x³ - x = 48x
=> x³ = 49x
=> x² = 49
=> x = 7
The numbers are 6 , 7 and 8.
______________________________________________________________
★★★★ HOPE THIS HELPS YOU ★★★★
★★★★ PLS MARK ME AS BRAINLIEST ★★★★
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