Math, asked by sandipu05, 1 year ago

find 3 rational no. between (a-b)^-1 and (a^-1-b^-1),given that a=1/6,b=1/8.

Answers

Answered by hussain036
1
(a-b)^-1 = 1/(a-b) = 1/(1/6 - 1/8) = 48/8-6 =48/2 = 24
and (a^-1 - b^-1) = (1/a -1/b ) = (1/1/6 - 1/1/8 ) = 6-8=-2
Now, 3 rational numbers between these numbers.
1. {24+(-2)}/2 =22/2=11
2. 24+11 / 2 = 35/2
-2+11 / 2 = 9/2
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