Math, asked by madhavjaihind8895, 9 months ago

Find 5 th term in the binomial expansion of (2x-7)^4​

Answers

Answered by SrijanAdhikari23
0

The fifth term in the binomial expansion of (2x-7)^4 is 2401

The expansion of a binomial's powers is described by the binomial theorem, a mathematical statement. The polynomial (x+y)^n can be expanded into a sequence of sums made up of terms of the type cx^ay^b;a,b\in W or we can say that a,b are non-negative integers and c is any integer.

The general term of a binomial expansion of (a+b)^n is given by :

T_{r+1}=^nC_ra^{n-r}b^r

The given binomial expansion is  (2x-7)^4 . Comparing the above expansion to this we get :

a=2x , b =-7

Now we have to find the 5th term of the expansion.

\therefore r+1=5\\or, r = 4

Using these values in the above formula for the general terms we get:

T_{5}= {}^4C_4\cdot(2x)^{4-4}\cdot(-7)^4\\or, T_{5}={}^4C_4\cdot(2x)^{0}\cdot(-7)^4\\or,T_5=1\cdot(1)\cdot(2401)\\or,T_5=2401

Therefore the 5th term in the binomial expansion of (2x-7)^4 is 2401.

Learn more about binomial expansion at:

https://brainly.in/question/54103632

https://brainly.in/question/54180503

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