find 'a' if (1,2) is a point on the locus y^2=4ax
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Answer:
a = 1
Step-by-step explanation:
To find---> Value of a if ( 1 , 2 ) is a point on the locus y² = 4ax .
Solution---> ATQ, y² = 4ax .............( 1 )
( 1 , 2 ) is a point on the parabola , so point
( 1 , 2 ) satisfiy the equation ( 1 ).
So satisfying the equation ( 1 ) by ( 1 , 2 ) ie putting
x = 1 and y = 2 , we get,
( 2 )² = 4 a ( 1 )
=> 4 = 4a
=> a = 4 / 4
=> a = 1
Addotional information--->
Equation of parabola
y² = 4 ax
1) Coordinate of vertex = ( 0 , 0 )
2) Coordinate of focus = ( a , 0 )
3) Length of latusrectum = 4a
4) Equation of directrix
x = - a
5) Equation of latusrectum
x = a
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