find a if 2^a-3 * 5^2a-5= 250
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Hello Dear Brainly user...
Solution for your
Question
Given that:-
2 ^ (a -3) × 5 ^ (2a -5) = 250
we know that;
Log m× n = log m + log n
and
Log m ^n = n × log m
Now,
Taking log on both side
Log { 2 ^ (a -3) × 5 ^ (2a -5) } = log 250
=> log 2 ^ (a -3) + log 5 ^ (2a -5) = log( 125 × 2)
=> (a -3) × log 2 + (2a -5) × log 5 = log (5³ × 2)
=>(a -3) × log 2 + (2a -5) × log 5 = log 5³ + log 2
=> a log2 - 3 log2 + 2a log5 - 5 log5 = 3 log 5 + log 2
=> By shifting...
=> a [ log 2 + 2 log5 ] = 3 log5 + log 2 + 3 log2 + 5 log5
=> a [ log 2 + 2 log 5] = 8 log 5 + 4 log 2
=> a [ log 2 + 2 log 5] = 4 { 2 log 5 + log 2}
By comparing...
=> a = 4 Answer
Hope it helps...
:-)
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