Question

find a number such that one fourth of it is less than its one seventh by 3

Answer 1

Let the no. be x

$\frac{1}{4} = x - \frac{1}{7} \times 3$

$\frac{1}{4} = x - \frac{3}{7}$

$\frac{1}{4} = \frac{7x - 3}{7}$

$\frac{1}{4} \times 7 = 7x - 3$

$\frac{7}{4} = 7x - 3$

$- 7x = - 3 - \frac{7}{4}$

$- 7x = \frac{ - 12 - 7}{4}$

$- 7x = \frac{ - 19}{4}$

$x = \frac{19}{4} \times \frac{1}{7}$

$x = \frac{19}{28}$