Question

find a number whose double is 45 greater than its half

Answer 1

Let the number be x
Therefore
$2x = 45 + \frac{x}{2}$
$2x = \frac{90 + x}{2}$
$4x = 90 + x$
$3x = 90$
$x = \frac{90}{3}$
$x = 30$
Therefore the number is 30

Hope it helps! ☺

Answer 2

Heya!
Here's your answer!
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$let \: the \: number \: be \: x$
$therefore \: the \: double \: of \: the \: \\ number \: is \: 2x$
$therefore \: the \: half \: of \: the \: \\ number \: is \: \frac{1}{2} x$


Now According to the question ,

$2x = 45 + \frac{1}{2} x$
$2x = \frac{90 + x}{2}$
$4x = 90 + x$
$3x = 90$
$therefore \: x = 30$
Hence the required number is 30

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Hope this helps!