Question

Find a point lying on X-axis which is equidistant from the point (7, 6) and (3, 4)

Answer 1

X =7+3=10/2=5
By the using mid point of coordinate geometry

Answer 2

let the point be(x,0)since it lies on the x-axis
then by distance formula we know that
(x-7)^2+36=(x-3)^2+16
so x^2+49+36-14x=x^2-6x+9+16
so we get -8x=-60
and hence x=7.5
so the point is(7.5,0)
jope it helped..
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