Question

Find a point on x-axis which is equal distance from the point 5-2 and -32?

Answer 1

let the point on y-axis be (0,y)

by using distance formula

[(6–0)

Squarring both sides and solving…..

36

61–10y=25–6y [y^2 cancel out]

36=4y

y=9

Point=(0,9)