Question

Find a point on X axis which is equidistant from the two points (3 , 5) and (1 , 3)​

Answer 1

Answer :-

$\sf\huge\boxed{x = 6}$

Solution :-

According to question,

=> (x - 3)² + (0 - 5)² = (x - 1)² + (0 - 3)²

=> x² - 6x + 9 + 25 = x² - 2x + 1 + 9

=> x² - 6x + 34 = x² - 2x + 10

=> x² - 6x + 2x - x² = 10 - 34

=> - 6x + 2x = 10 - 34

=> - 4x = - 24

=> 4x = 24

=> x = 24/4

=> x = 6

Hence, the value of x is 6

Answer 2

Answer:

= (x - 3)^2 + (0 - 5)^2 = (x - 1)^2 + (0 - 3)^2

= x^2 - 6x + 9 + 25 = x^2 - 2x + 1 + 9

= x^2 - 6x + 34 = x^2 - 2x + 10

= x^2 - 6x + 2x - x^2 = 10 - 34

= - 6x + 2x = 10 - 34

= - 4 = - 24

= 4x = 24

x = 24/4

x = 6 .