Question

Find a point on y-axis which is at equal distances from points P (3,2) and Q(-1,-5)​

Answer 1

Answer:

Step-by-step explanation:

Hope you got it. And it helps you

Answer 2

Step-by-step explanation:

given points P(3,2) and Q(-1,-5)

let point on y-axis be M (0,y)

PM=√(3-0) ^2 + (2-y) ^2

=√(3) ^2+(2) ^2+(y) ^2-2.(2) . (y)

= √9+4+y^2-4y

=√y^2-4y+13

QM= √(-1-0) ^2+(-5-y) ^2

= √(-1) ^2+(-5) ^2+(y) ^2-2.(-5). (y)

√1+25+y^2-10y

=√y^2-10y+26

now,

PM=QM

y^2-4y+13=y^2-10y+26

-4y+10y =26-13

6y = 13

y=13/6

point (0,13/6)