Math, asked by nitu00967, 23 days ago

find a quadratic polynomial each with the given number as the sum and product of its zeros respectively: 1/6,-1/3​

Answers

Answered by sshavy567
2

Answer:

Sum of zeroes = 1/6 (s)

Product of zeroes = -1/3 (p)

Quadratic polynomial = K ( x^2 - sx + p )

= K ( x^2 - 1/6x + (-1/3)

= K ( x^2 - 1x - 2 / 6)

= K/6 ( x^2 - x - 2 ) where K is some

constant.

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