Question

find a quadratic polynomial the sum and product of zeros are - 3 and - 7 respectively ​

Answer 1

Answer:

x^2 +3x-7

Step-by-step explanation:

According to the formula:-

x^2-(Sum of zeros)x + Product of zeros

x^2-(-3)x + (-7)

= x^2 +3x-7

Answer 2

$\Huge{\underline{\underline{\red{\sf{Answer :}}}}}$

$\tt given \begin{cases} \sf{sum \: and \: product \: are \: - 3 and \: - 7 \: respectively} \end{cases}$

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To Find :

We have to find quadratic polynomial

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Solution :

We have formula for finding polynomial

$\Large{\underline{\boxed{\sf{x^2 \: - \: (sum)x \: + \: product }}}}$

Put Values,

⇒x² - (-3)x + -7

⇒x² + 3x - 7

⇒x² + 3x -7

∴ Polynomial is x² + 3x - 7

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Proof :

Polynomial is x² + 3x - 7

Where,

a = 1, b = 3 , c = -7

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For finding sum of zeros we have formula

Sum of zeros = -b/a

⇒Sum of zeros = -(3)/1

⇒Sum is -3

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And For product is :

Product of zeroes = c/a

⇒ Product = (-7)/1

⇒ Product is -7

$\rule{200}{2}$

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