Find a quadratic polynomial whose sum and product respectively of the zeros are 21/8 and 5/16
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Heya !!!!
This is your answer......
Given :----
Sum of zeroes, (a+b) = 21/8.
Product of zeroes, (ab) = 5/16.
General formula of quadratic equation is..
.............
p(x) = kx^2 -(a+b)x + ab
Putting values .....
p(x) = x^2 - (21/8)x + 5/16.
x^2 - 21x/8 + 5/16 = 0
Multiplying both sides by 16.....
We get....
16x^2 - 42x + 5 = 0.
Hence.. the required equation is 16x^2 - 42x + 5 = 0.
Hope it helps....
This is your answer......
Given :----
Sum of zeroes, (a+b) = 21/8.
Product of zeroes, (ab) = 5/16.
General formula of quadratic equation is..
.............
p(x) = kx^2 -(a+b)x + ab
Putting values .....
p(x) = x^2 - (21/8)x + 5/16.
x^2 - 21x/8 + 5/16 = 0
Multiplying both sides by 16.....
We get....
16x^2 - 42x + 5 = 0.
Hence.. the required equation is 16x^2 - 42x + 5 = 0.
Hope it helps....
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