Find a quadratic polynomial whose zero are
-9and-1/9
ParthThakre9965:
is anything else given?
Answers
Answered by
4
sum of zeroes =(-9)
Product of zeroes =(-1/9)
sum of zeroes =(-b) /a
Hence b=-(-9)=9
Product of zeroes =c/a
hence c=(-1)
and a=9
Hence quadratic equation =9x²+9x-1
Product of zeroes =(-1/9)
sum of zeroes =(-b) /a
Hence b=-(-9)=9
Product of zeroes =c/a
hence c=(-1)
and a=9
Hence quadratic equation =9x²+9x-1
Answered by
2
Step-by-step explanation:
α = -9 β = -1/9
quadratic polynomial
= k {x ²- (α + β)x + αβ}
= k { x² - (-9 - 1/9)x -9 x -1/9}
= k { x² - (-19/9)x + 1}
= k { x² + 19/9 x + 1}
when k = 1
the quadratic polynomial is x² + 19/9 x + 1
Hope it helps!!
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