Math, asked by stevenst12, 1 year ago

Find a quatric polynomial P(y) whoes sum and product of zeroes are - 1/3 respectively


mysticd: Product of the zeroes = -1/3
mysticd: Sum of the zeroes = -1/3
mysticd: Is it right Stevenst
Anonymous: No this is the question of ncert
Anonymous: By mistake this question was reported by me

Answers

Answered by jakeer1
3
1/4 , -1 (ii) √2 , 1/3 (iii) 0, √5 (iv) 1,1 (v) -1/4 ,1/4 (vi) 4,1
(i)1/4, -1
Now formula of quadratic equation is
x²-(Sum of root)x + (Product of root) = 0
Plug the value in formula we get
x² –(1/4)x -1 = 0
Multiply by 4 to remove denominator we get
4x² - x -4 = 0
(ii) √2 , 1/3
Now formula of quadratic equation is
x²-(Sum of root)x + (Product of root) = 0
Plug the value in formula we get
x² –(√2)x + 1/3 = 0
Multiply by 3 to remove denominator we get
3x² - 3√2 x + 1 = 0
Answered by Anonymous
0
Hello friend

Good afternoon

❤❤❤❤❤❤❤❤❤❤❤❤❤❤

Your answer is given in the attachment

I hope it will help you

Thanks

Have a great day friend

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Attachments:

mysticd: It is wrong
Anonymous: .....Question is also..
Anonymous: If sum => -1
Anonymous: Product => 3 then my ans is correct
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