Question

Find a unit vector parallel to 3i+2j-k, i really need it fast!

Answer 1

Answer:

Find the unit vector parallel to 3a − 2b + 4c if a = 3i − j − 4k, b = −2i + 4j − 3k, and c = i + 2 j − k. Solution : ... 3(3i − j − 4k) - 2(−2i + 4j − 3k) + 4(i + 2j − k)

Answer 2

Explanation:

Note that the length of the given vector, a=3i+2j−k is 9+4+1−−−−−−−√.

Hence b=a14√ is a unit vector having the same direction as that of a.

Hence b=4a14√=12i14√+8j4k√−4k14√ is the required vector.

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