Question

Find a unit vector that is perpendicular to u = (2, 3, 4) and v = (-1, 3, -5).​

Answer 1

Answer:

Explanation:

vector u = 2i+3j+4k

vector v = -i+3j-5k

As we know the vector perpendicular to both u and v is (u × v).

| u × v | = (-3*5-4*3) i - (-5*2+4*1) j - (2*3+3*1) k

| u × v | = -27i+6j-9k

magnitude of u × v is √(27^2+6^2+9^2) = √846

hence unit vector =  (-27i+6j-9k) / √846