find ab where a and b are 0^2 and 0^2
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Let A(−a,−b),B(0,0),C(a,b) and D(a2,ab)
Distance between two points (x1,y1) and (x2,y2) can be calculated using the formula (x2−x1)2+(y2−y1)2
Distance between the points A(−a,−b) and B (0,0)=(0+a)2+(0+b)2=a2+b2
Distance between the points B(0,0) and C (a,b)=(a−0)2+(b−0)2=a2+b2
Distance between the points C(a,b) and D (a2,ab)=(a2−a)2+(ab−b)2=(a−1)a2+b2
Distance between the points A(−a,−b) and D (a2,ab)=(a2+a)2+(ab+b)2=(a+1)a2+b2
Now.
AB+BC+CD=a2+b2+a2+b2+(a−1)a2+b2=(a+1)a2+b2=AD
Hence, the points are collinear.
Hence, the points are collinear.
Step-by-step explanation:
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